SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

block;width:300px;height:250px" data-ad-client="ca-pub-6421572098224086" data-ad-slot="3363741150">

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ | This post give current answers on waec gce, waec gce expo waec gce answers, gce waec runz, gce waec exam answers 2017 2018 and beyond – SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ – TODAY’S BIOLOGY PRACTICAL ANSWERS Neco answers.Waec Gce 2017 General Mathematics Obj And Theory Answers – Nov/Dec Expo Now Available.

“); }10a)
YX/XZ=XM/MZ
W/10=8/15
15W=10*8 W=5.33cm.

10bi)
q^2=p^2+r^2-2prcos tita
q^2=20^2+15-2*20*15 c0s 90
q^2=400+225-0
q^2=625 q=sqroot625
q=25km.

10bii)
p/sinP=q/sinQ=r/sinR
25/sin90=15/sinR
sinR=15*1/25 sinR=0.6
R=sin^-1(0.6)
R=36.86degrees
The bearing of p from R
=90+90+90+alpha
alpha=45-36.86 =90+90+90+8.14
=278.14
=278degrees
The bearing of p from R=278degrees.

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

==================================
9a)
CBA=180-(128-x) sum of angle on a straight line
CBA=52+x
ADC=180-(128-x)
=52+x
Also BCD=180-x(angle on a straight line)
DCQ=180-(180-x) DCQ=180-180+x
DCQ=x
x+52+x+76=180
2x=180-52-76
2x/2=52/2
x=26degrees.
=====================================
8a)
diagram
(8+x)^2 = x^2+32
64+16x+x^2= x^2 + 1024
16x=1024-64=960
therefore 960/16= 60 x=960/16
=60
therefore the radius = 60+8
=68cm.
=====================================
8b)
diagram
(i)volume of a pyramid
=1/3 AH
2601= 1/3 * A * 27
A=7803/27
=289cm^3
Area of square =289 t^2= 289
t= sqr rut(289)
l=17cm.

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

8bii)
AC^2 = 17^2 +17^2
AC^2 = 289 +289 Ac^2 =578
AC =sqr root (578)
AC=24.04cm
for the triangele COP
CO= 1/2 AC
=1/2 * 24.04 VC^2= 27^2 + 12.07
VC^2= 929 +144.49
VC= SQR root (873.48)
=29.55cm
cos tita = ADJ/hyp
cos x= 8.5/29.55 cos x=0.2877
x=cos^-1 0.2877
=73.66 degree.
==========================
1a)
1/2log 25/4- 2log10 4/5+log10 320/125
Firstly Log(25/4)^1/2-log(4/5)^2+log10 320/125
Log10 sqrt25/4-log16/25+log10 320/125
Log10 5/2-log10 16/25+log10 320/125
Furthermore – Log10 5/2+log10 320/125-log10 16/25
Log10 [5/2*320/125÷16/25]
Log10 [5/2*320/125*25/16]
Lastly – Log10 10=1.

1b)
% income= 20%
Grant per land =GHC€15.00
Total population from
2003-2007
=1.2*1.2*1.2*1.2*3000=6220.8
Total grant=population*grant per head
=6220.8*15
=ghc€93312
Total grant=GHC€93312.

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
2a)
1/x+1/x+3=1/2
L.C.M=x(x+3)
X+3+x/x(x+3)=1/2
2(2x+3)/x(x+3)=1/2
2(2x+3)=x(x+3)
4x+6=x^2+3x
X^2+3x=4x+6
X^2+3x-4x-6=0
X^2-x-6=0
(X^2-3x)+(2x-6)=0
X(x-3)+2(x-3)=0
(X+2)(x-3)=0
X=-2 or x=3.

2b)
Let d bag of rice be X
Let d bag of beans be Y
X+Y=17—>(I)
2250x+2400y=39600—>(2)
From eqtn (I)
X=17-y
Using elimination method to eliminate Y
2250x+2250y=38250—>(3)
2250x+2400y=39600—>(4)
Eqtn 4- eqtn 3
2400x-2250x = 39600-38250
150x=1350
X=1350/150
X=9
D trader bought 9bags of beans.

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
(3)
=Draw The Diagram=
CLICK HERE TO VIEW THE DIAGRAM
Area of path –> 2[1/2 (x+2)] + 2(x+1) = 17
x + 2 + 2x = 17
3x + 2 = 17
3x = 17 – 2
also 3x = 15
x = 15/3
x = 5.

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ | waec gce expo waec gce answers, gce waec runz, gce waec exam answers 2017 GMathe Obj & Theory AnswersSIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ | waec gce expo waec gce answers, gce waec runz, gce waec exam answers 2017 GMathe Obj & Theory Answers.

(a) Perimeter of garden
= 4x
= 4 x 5
= 20m.

(3b)
=Draw The Diagram=
CLICK HERE TO VIEW THE DIAGRAM
Area Covered By Both Garden And path
= (x+1) (x+2)
= (5+1) (5+2)
= 6×7
= 42m^2.

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
(4a)
Given: Sinx = 3/5
i.e
=Draw The Diagram=
CLICK HERE TO VIEW THE DIAGRAM
Using pythogoras triple 3,4,5
CosX + TanX/SinX
=4/5 + 3/4 ÷ 3/5
= 16+15/20 ÷ 3/5
= 31/20 ÷ 3/5
= 31/20 x 5/3
lastly = 31/12.

(4b)
=Draw The Diagram=
CLICK HERE TO VIEW THE DIAGRAM
Reflex P’Q’T + R’Q’T + P’Q’R = 360 (sum at a point)
200 + 32 + P’Q’R = 360
232 + P’Q’R = 360
P’Q’R = 360 – 232
P’Q’R = 128°
From the Diagram
Q’R’U = P’Q’R = 128° (alternate angles)
Firstly X = Q’R’U + S’R’U
X = 128° + 180
X = 308°.

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
5a)
=Draw The Diagram=
CLICK HERE TO VIEW THE DIAGRAM
1. | 2. | 3. | 4. | 5. | 6. |
——————————————
1|1,1|1,2 |1,3 |1,4 |1,5 |1,6 |
——————————————-
2|2,1|2,2 |2,3 |2,4 |2,5|2,6 |
——————————————–
3|3,1|3,2 |3,3 |3,4 |3,5|3,6 |
———————————————
4|4,1|4,2 |4,3 |4,4 |4,5|4,6 |
———————————————
5|5,1|5,2 |5,3 |5,4 |5,5|5,6 |
———————————————–
6|6,1|6,2 |6,3 |6,4 |6,5|6,6 |
————————————————

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

B) pr(sum of outcome is 8)
= 4/36 = 1/9
Bii) pr(product of outcom <10)
= 30/36 = 5/6
Biii) pr(outcom contain atleast a 3)
= 24/36 = 4/6
= 2/3.
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
(6a)
2 X (37)x = 75x
2 X (3x + 7)10 = (7x + 5)10
Finally 2 (3x + 7) = 7x + 5
6x + 14 = 7x + 5
14 – 5 = 7x – 6x
9 = x
:- x = 9.

(6b)
Let The Number Of boys be X
Number Of girls in class = x + 5
GIVEN: x+5/+2 = 5/4
5(x+2) = 4(x+5)
5x + 10 = 4x + 20
5x – 4x = 20 – 10
x = 10
(i)Numbers of girsl in class
= x + 5
= 10 + 5
= 15
(ii)Total number of students
= x + x + 5
= 10 + 10 + 5
= 25
(iii)Probability of selecting a boy as class prefect
= 10/24
= 2/5.

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
7a)
|PQ|^2 = |PB|^2 + |BQ|^2
|PQ|^2 = (5 – x )^2 + X^2
Furthermore |PQ|^2 = 25 – 10x + x^2 + x^2 [note ^ means Raise to power]
|PQ|^2 = 2x^2 – 10x + 25
NB: PQ = QR (side of a square)
Area of PQRS = PQ x QR
= PQ x PQ = PQ^2
Area of PQRS = (2x^2 – 10x + 25)m square
GIVEN: 2x^2 – 10 + 25 = 3/5 of 25
= 2x^2 – 10x + 10 = 0
= x^2 – 5 + 5 = 0.

Using General Formular mthod
X = -(-5) ± Square Root (-5)^2 – 4(1)(5)/ (2 x 1)
X = 5 ± Square Root 25 – 20/ 2
Furthermore X = 5 ± Square Root 5 / 2
X = 5 + Square Root 5 / 2 OR 5 – Square Root 5 / 2
X = 3.62 or 1.68.

7b )
L + a / n – 1 = d ———— (I)
2s = n (a + 1) —————- (2)
From eq (1)
L + a = d (n – 1) ————– (3)
Put eq (3 into 2)
2s = nd (n-1)
2s = d (n^2 – n)
S = d ( n^2 – n ) / 2 or
S = dn(n-1)/2.
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°.

SIMPLIFIED WAEC GCE MATHEMATICS EXPO ANSWERS & RUNZ

8a)
By using pythagoras
r^2 = (r – 8)^2 + 32^2
r^2 = r^2 – 16r + 64 + 1024
16r = 64 + 1024
r = 1088/16
r = 68
r=68cm
8bi)
{st/pt/
q2=27^2 +12^2
q=sqrt27^2 + 12^2
q=sqrt729+144
q=sqrt873
q=29.5cm.
================================
Good Luck

Related Post

2018 NABTEB | WAEC 2018 | NECO 2018 | GCE FORM 201... 2018 NABTEB | WAEC 2018 | NECO 2018 | GCE FORM 2018 | EXAM REGISTRATION SCRATCH CARD & EXAM FEES HOW MUCH IS NABTEB, WAEC, NECO GCE FORM 2018/2019...
LATEST NEWS JAMB MOCK EXAMS RELEASED LEARNED STEPS... LATEST NEWS JAMB MOCK EXAMS RELEASED LEARNED STEPS TO JAMB RESULT CHECKERS LATEST NEWS JAMB MOCK EXAMS RELEASED LEARNED STEPS TO JAMB RESULT CHECKERS ...
WAEC EXPO ANSWERS MATHEMATICS EXPO RUNZ 2018 MATHS... WAEC EXPO ANSWERS MATHEMATICS EXPO RUNZ 2018 MATHS ANSWERS FREE Study mathematics to show thy self approved - WAEC EXPO ANSWERS MATHEMATICS EXPO RUNZ ...
Today’s NECO Geography 2017 Obj and Essay | ... Today's NECO Geography 2017 Obj and Essay | Questions and Answers Expo Runz Today's NECO Geography 2017 Obj and Essay | Questions and Answers Expo Run...
FULLY LOADED WAEC PHYSICS GCE 2017 ANSWERS EXPO RU... FULLY LOADED WAEC PHYSICS GCE 2017 ANSWERS EXPO RUNZ WAEC GCE Physics Questions 2017 | Check OBJ and Theory Answers Here | FULLY LOADED WAEC PHYSICS G...
JAMB NEW ADMISSION POLICY – UTME POLICY PROC... JAMB NEW ADMISSION POLICY - UTME POLICY PROCESSES JAMB NEW ADMISSION POLICY - UTME POLICY PROCESSES - JAMB PROCESSES - JAMB NEW ADMISSION METHOD 2017/...
2017 NECO Bomb GCE Timetable Official – Nov/... 2017 NECO Bomb GCE Timetable Official - Nov/Dec Latest Update 2017 NECO Bomb GCE Timetable Official - Nov/Dec Latest Update - This is the official 201...
WORKED OUT NECO ANSWERS FOR COMPUTER STUDIES EXPO ... WORKED OUT NECO ANSWERS FOR COMPUTER STUDIES EXPO ANSWERS RUNZ WORKED OUT NECO ANSWERS FOR COMPUTER STUDIES EXPO ANSWERS RUNZ - FRESH NECO COMPUTER SC...
2018 My Costume Scholarship In United State Applic... 2018 My Costume Scholarship In United State Application Guide and Requirement 2018 My Costume Scholarship In United State Application Guide and Requir...
Delta State University, DELSU Update on Awaiting R... Delta State University, DELSU Update on Awaiting Result Candidate - This is a very important Information, therefore we urge all interested readers to ...
Agric Practical & Specimen Expo 2017 WASSCE A... Agric Practical & Specimen Expo 2017 WASSCE Answers¬2017/2018 WAEC Specimen. Agric Practical waec specimen 2017, waec biology specimen 2017, waec...
COMPLETE & VERIFIED 2017 FURTHERMATH NECO ANS... COMPLETE & VERIFIED 2017 FURTHERMATH NECO ANSWERS COMPLETE & VERIFIED 2017 FURTHERMATH NECO ANSWERS All in one answers. As a matter of fact t...
List Of Best Universities in Nigeria to Study Law ... List Of Best Universities in Nigeria to Study Law - Best Law Universities in Nigeria List Of Best Universities in Nigeria to Study Law - Best Law Univ...
Affirmed Neco Literature in Arabic. Arabic General... Affirmed Neco Literature in Arabic. Arabic General Answers Expo Runz. Affirmed Neco Literature in Arabic. Arabic General Answers Expo Runz. CONFIRMED ...
SIMPLIFIED NECO CIVIC EDUCATION ANSWERS/EXPO &... SIMPLIFIED NECO CIVIC EDUCATION ANSWERS/EXPO & RUNZ 2017/2018 SIMPLIFIED NECO CIVIC EDUCATION ANSWERS/EXPO & RUNZ 2017/2018 Presently see SIM...
NECO CHRISTIAN RELIGIOUS KNOWLEDGE/STUDIES PAST Q... NECO CHRISTIAN RELIGIOUS KNOWLEDGE/STUDIES PAST QUESTIONS & ANSWERS EXPO 2017 Past Questions, Expo 2017, NECO Obj & Theory NECO CHRISTIAN R...
READ  60% GOOD GRADE MATHS & ENGLISH WAEC RELEASES 2017 MAY/JUNE EXAM RESULTS

Leave a Reply

Your email address will not be published.