Real GCE Physics Question and Answer 2018 OBJ/ESSAY/PRACTICALS – WAEC GCE Physics complete Questions 2018 | Check OBJ & Theory Answers. WAEC | WAEC GCE Physics Practical Questions 2018… Here you will get both essay answers, objective answers and GCE Physics laboratory apparatus that will be used for the 2018 Physics Practical Examination. Stay focus and study through.

Real GCE Physics Question and Answer 2018 OBJ/ESSAY/PRACTICALSWAEC GCE Physics Practical Questions 2018

The West African Examinations Council (WAEC) is an examination board that conducts the West African Senior School Certificate Examination, for University and Jamb entry examination in West Africa countries. … In a year, over three million candidates registered for the exams coordinated by WAEC.

General Certificate Examination (GCE) 2018 Waec Physics alternative to practical paper will be written on Wednesday, 5th September, 2018 from 9:30am to 12:15 pm.

As a matter of fact, we made this post to highlight samples of the Specimens, alternative to practical graphs and calculations that was used in the Chem Practical Examination past questions and syllabus.

WAEC GCE Physics Practical Questions 2018

Keep accessing this page as update will be made in a jiffy

(1a)

Pls Tabulate:

xi(cm)|yi(cm)|zi(cm)|W1(Nx10^-2)|W2(Nx10^-2)|u=(w1-w2)(Nx10^-2)|v=(w1-w3)(Nx10-2)

=>1.80|1.50|1.70|3.6|3.00|3.40|0.60|0.20

=>3.80|3.00|3.00|7.6|6.00|6.00|1.60|1.60

=>5.50|4.40|5.00|11.10|8.00|10.00|2.20|1.00

=>7.30|5.90|6.60|14.60|11.80|13.00|2.80|1.40

=>9.20|7.30|8.30|18.40|14.60|16.60|3.80|1.80

=>11.10|8.30|10.00|22.20|16.60|20.00|5.60|2.20

(1b)

Relative density, or specific gravity, is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. Specific gravity usually means relative density with respect to water.

(1bii)

Given volume of solid immersed

Vsi =1/2*30cm³

=15cm³

Density of liquid (water)ew= 1g/cm³

Acceleration due to gravity, g = 10m/s²

Upthrust, U= eVsi g

U= 1000*(15*10^-6)*10

U=15*10-²

U=0.15N

Weight of solid =mg

=EsVs g

given: Es=2.4g/cm³ (2400kg/m³)

Vs=30cm (30*10^-6 m³)

g=10m/s²

Weight, w=30*10^-6*2400*10

=72*10-²

=0.72N

Reading on spring balance =W-U

=0.72-0.15

=0.57N

===============================

(3aiv)

Tabulate pls:

S/n: 1,2,3,4,5,6

R/ohms: 0.00,1.00,2.00,3.00,4.00,5.00

I/A: 3.00,1.00,0.60,0.45,0.35,0.25

P=(E/I) V ohms^-1: 0.500,1.500,2.500,3.333,4.286,6.000

(3vi)

s=Y1-Y2/X2-X1 = 4-2/3.6-1.5

=2/2.1

=0.952

(3vii)

C = 0.5ohm

(3viii)

Resistance

(3ix)

-I ensured that the circuit is open after each reading to maintain the E.M.F of the battery

-I ensured that the Zero Error of the Ammeter is checked and noted

(3bii)

V = 4.5v

R = 4ohms

I = 0.9A

V = I(R+r)

where r = internal resistance

4.5 = 0.9(4+r)

.:. 4+r = 4.5/0.9

4+r = 5

r = 5-4

= 1 ohm.

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Real GCE Physics Question and Answer 2018 OBJ/ESSAY/PRACTICALS

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