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## PERFECT WAEC MATHEMATICS EXPO RUNZ 2018 – MATHS QUESTIONS AND ANSWER FREE

WAEC 2018 Mathematics Obj And Essay Answer – May/June Expo – PERFECT WAEC MATHEMATICS EXPO RUNZ 2018 – MATHS QUESTIONS AND ANSWER FREE – 2018 WAEC LIVE ANSWERS HOT WAEC 2018 Mathematics Obj And Essay Answer – Expo – This is random repeated questions and answers 2018 mathematics examinations. No doubt questions in this year exam will be repeated, therefore we urge you to be careful while making use of this site.

## WAEC GCE Mathematics Obj And Essay/Theory Solution Questions and Answer – 2018 Expo Runz.

3a)
[Diagram]
Distance covered by an athlete = Perimeter of A + Perimeter of rectangle CDEF + perimeter of B
Perimeter of A = 2πr/2 = π =22/7, r = d/2 = 120/2 = 60m
= 22/7 × 60 = 1320/7 = 188.57m

Perimeter of B = perimeter of A = 188.57m
Perimeter of rectangle CDEF= 2(L + B)
L = 120m; B = 60m
Perimeter = 2(120+60) = 2(180)
=360m
Distance covered by an athlete = 188.57 + 360 + 188.57
=737.14m
If the athlete runs the track two times = 2 × 737.14
= 1474.28m

3b)
If the athlete spends 200 seconds for the race
Speed = distance/time
Distance = 1474.28m
Time = 200second
Distance = 1474.28m = 1.47428km
Time= 200seconds = 3.3333hrs
Speed = 1.47428/3.3333 = 0.44kmhr-1

11a)
Loga(y + 2) = 1 + LogaX
=> Log^y a + Log^2 a = Log^a a + Log^x a

Loga^(y + 2) = Loga^(ax)

Y + 2 = ax
Hence y+2/a = ax/a
X = y+2/a

11bi)
Bibiani = 600
Amenji = 700
Oda = 1800
Wawso = 1500
Sankose=2400
Total = 7200

Bibiani = 600/7200 × 360/1 = 30°
Amenji = 700/7200 × 360/1 = 45°
Oda = 1800/7200× 360/1 = 90°
Wawso = 1500/7200× 360 = 75°
Sankose = 2400/7200× 360/1 = 120°
Total = 30°+45°+90°+75°+120° = 360°

11bii)
% of timber produced from Amenji = 900/7200 × 100/1 = 12.5%

11biii)
Revenue received by Bibiani = 600×\$560 = \$336,000
Revenue received by Oda = 1800×560 = \$1,008,000
Oda will receive(1,008,000 – 336000) = \$672,000 more than Bibiani.

## 4a) Rate = 2/100 * N0.02 per month Rate per annum = 0.02 * 12 = 0.24 per annum4b) Draw the Diagram

6a)
Tanx = 5/12
Using the diagram
Sinx = 5/13
Cosx = 12/13
Sinx/(sinx)² + cosx = 5/13/(5/13)² + 12/13
= 5/13all over 25/169 + 12/13
= 5/13/25+156/169
=5/13/181/169
= 5/13 × 169/181 = 65/18

6b)

# WAEC 2018/2019 FINAL ANSWERS CHECK HERE

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Real and Confirmed WAEC GCE Maths Questions and Expo Answer hope this has helped alot.

Verified WAEC GCE 2018 Mathematics OBJ and Essay Answer and Solution to the questions.

GOODLUCK!!!.

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