2017 NECO GCE MATHEMATICS OBJ: CONFIRM

1-10: EAACBAECBE
11-20: CDABECBCCA
21-30: AEDCBACEDE
31-40: ADADCCDABD
41-50: BCEBDCEABE
51-60: DBAECBECBE

1A
(6Y²)³ / 2 Y^6
= 6³Y^6 / 24Y^6
=6³Y^6/24Y^6
= 216/24
=9

1B
LOG10(2M² 5M-2)=1
2M² 5M-2=10
2M² 5M-2-10=0
2M² 5M-12=0
USING M=-B -√B²-4AC/2A
A=2
B=5
C=-12
M=-5 -√5²-42(-12)/2*2
M=-5 -√2 96/4
M=-5 -√98/4
M=-5 -9.9/4
M=-5 9.9/4 OR M=-5-9.9/4
M=1.225 OR -3.725

(2A)
W~ 3√D
LET OUR CONSTANT BE K
W= K×3√D
10= K × 3√27
10/3= 3K/3
K= 10 /3
W WHEN D= 64
W= 10/3 × 3√64
W= 10/3 × 4
W= 40/3
W= 13.3

2017 NECO GCE MATHEMATICS OBJ: CONFIRM

(2B)
X/2 Y/6 = 2/3
L.C.M = 6
RX Y = 4 —–(1)
X/3 – Y/2 = 5/3
L.C.M = 6
2X – 3Y = 10 —–(2)
FROM EQ (1)
3X Y = 4
Y= 4 – 3X ——(3)
SUB FOR Y IN EQ (2)
2X – 3(4-3X) = 10
2X – 12 9X = 10
11X = 22
X=2
SUB FOR X IN EQ (3)
Y = 4-3(1)
Y = 4-3-
Y = 1

(4A)
V= 2/3ΠR
1527.4= 2/3 ×22/7 ×R
1527.4= 44R/21
32075.4= 44R
R= 32075.4/44
R= 728.98
~~~= 729CM

(4B)
3^3Y 1 = 81^-5
3^3Y 1 = 3^-4Y
3Y 1= -4Y
3Y 4Y= -1
7Y = -1
7Y/7= -1/7
Y= -1/7

(5A)
RED=4
GREEN = 6
BLACK= 10
TOTAL=20
(I) P(RED) = 4/20 = 1/5
(II) P(GREEN)= 6/20 = 3/10
(III) P (BLACK)= 10/20= 1/2

(5B)
( X-1)(X-8) 12=0
X²-8X-X 8 12=0
X²-9X 20=0
X= -B √B²-4AI
X= 9 /-√-9²-4×1×20÷ 2×1
X=9 /-√81-80÷2
X=9 /-√1÷2
X= 9 1/2 OR 9-1/2
X= 10/2 OR 8/2
X= 5 OR 4

(8A)
4A^2 B3AB^-2/4A^3(3AB)
=12 A^4 B^1/12A^4 B
=6^-1/B^1
=B^-1-1 =B^2
6^-2 OR 1/B^2

8B)
LET THE POCKET MONEY BE X
2X/5 =STATIONS
X/4=SCHOOL LEVIES
X/6= FOOD
X-(24X/5 X/4 X/6)=55
X-(24X 15X 10X)/60 =55
X-49X/60 =55
60X-60-49X/60 = 5560
60X-49X=#3,300
11X/11=3300/11
X=#300
THE POCKET MONEY =#300

8C)
16^X-4 = 64^X 4/8^X
24^X-16 = 2^6X 24/2^3X
2^4X-16 = 2^6X 24-3X
2^4X-16 = 2^3X 24
4X-16 = 3X 24
4X – 3X = 16 24
X = 40

10)
1/27^(X-2)=9^(2-X)
3^3(X-2)-1=3^2(2-X)
3-1(X-2)=4-2X
2X-4=4-2X
2X 2X=4 4
4X=8
X=
8/4
X=2

10B
5X Y/X 5Y= 3/1
5X Y= 3(X 5Y)
5X Y=3X 15Y
5X-3X=15Y-Y
2X=14Y
X/Y= 14/2 =7, Y/X= 1/7
X2-Y2/4XY

2017 NECO GCE MATHEMATICS OBJ: CONFIRM

DIVIDE ALL THROUGH BY MY
(X²- Y²/) ÷(4XY/XY)
XY- XY
(X/Y- Y/X) ÷4
(7- 1/7)÷4 ~~~49-1/7×1/4
48/7× 1/4= 24/7
= 4

11A)
A=(1 7,3 2) AND B=(2 5,4 6)
I)A^-1=1/DET(2 -7,-3 1)
DET= 2 -21=-19
A^-1=1/-19(2 -7,-3 1)
-1/19(2 -7,-3 1)
II)B^T =(2 -4,5 6)
III)AB =(1 7,3 2) (2 5,4 6)
(2 -28,6-8, 5 46,15 12)
(-26,-2, 51,27,)

11B)
7X^2 12X 5 = 0
7X^2/7 12X/7 = -5/7
X^2 12X/7 = -5/7
X^2 12X/7 (6/7)^2 – -5/7 (6/7)2
(X 6/7)^2= -5/7 36/49
(X 6/7)^2 = -35 36/49
(X 6/7)^2 = 1/49
(X 6/7) = AND – √1/19
X 6/7 = AND – 1/7
X = -6/7 AND – 1/7
X = -6 1/7 OR -6-1/7
X= -5/7 OR -7/7
X = -5/7 OR -1

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